4(c-2)=5(3+c)

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Solution for 4(c-2)=5(3+c) equation: 



4(c-2)=5(3+c)

We move all terms to the left:

4(c-2)-(5(3+c))=0

We add all the numbers together, and all the variables

4(c-2)-(5(c+3))=0

We multiply parentheses

4c-(5(c+3))-8=0



We calculate terms in parentheses: -(5(c+3)), so:

5(c+3)

We multiply parentheses

5c+15

Back to the equation:

-(5c+15)



We get rid of parentheses

4c-5c-15-8=0

We add all the numbers together, and all the variables

-1c-23=0

We move all terms containing c to the left, all other terms to the right

-c=23

c=23/-1

c=-23

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