4(c-2)=5(3+c)

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Solution for 4(c-2)=5(3+c) equation:



4(c-2)=5(3+c)
We move all terms to the left:
4(c-2)-(5(3+c))=0
We add all the numbers together, and all the variables
4(c-2)-(5(c+3))=0
We multiply parentheses
4c-(5(c+3))-8=0
We calculate terms in parentheses: -(5(c+3)), so:
5(c+3)
We multiply parentheses
5c+15
Back to the equation:
-(5c+15)
We get rid of parentheses
4c-5c-15-8=0
We add all the numbers together, and all the variables
-1c-23=0
We move all terms containing c to the left, all other terms to the right
-c=23
c=23/-1
c=-23

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