4(c-20)=5(c-6)

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Solution for 4(c-20)=5(c-6) equation: 



4(c-20)=5(c-6)

We move all terms to the left:

4(c-20)-(5(c-6))=0

We multiply parentheses

4c-(5(c-6))-80=0



We calculate terms in parentheses: -(5(c-6)), so:

5(c-6)

We multiply parentheses

5c-30

Back to the equation:

-(5c-30)



We get rid of parentheses

4c-5c+30-80=0

We add all the numbers together, and all the variables

-1c-50=0

We move all terms containing c to the left, all other terms to the right

-c=50

c=50/-1

c=-50

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