4(c-3)+3=2+c-11

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Solution for 4(c-3)+3=2+c-11 equation: 


Simplifying
4(c + -3) + 3 = 2 + c + -11

Reorder the terms:
4(-3 + c) + 3 = 2 + c + -11
(-3 * 4 + c * 4) + 3 = 2 + c + -11
(-12 + 4c) + 3 = 2 + c + -11

Reorder the terms:
-12 + 3 + 4c = 2 + c + -11

Combine like terms: -12 + 3 = -9
-9 + 4c = 2 + c + -11

Reorder the terms:
-9 + 4c = 2 + -11 + c

Combine like terms: 2 + -11 = -9
-9 + 4c = -9 + c

Add '9' to each side of the equation.
-9 + 9 + 4c = -9 + 9 + c

Combine like terms: -9 + 9 = 0
0 + 4c = -9 + 9 + c
4c = -9 + 9 + c

Combine like terms: -9 + 9 = 0
4c = 0 + c
4c = c

Solving
4c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
4c + -1c = c + -1c

Combine like terms: 4c + -1c = 3c
3c = c + -1c

Combine like terms: c + -1c = 0
3c = 0

Divide each side by '3'.
c = 0

Simplifying
c = 0

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