4(c-3)+5=3+c-10

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Solution for 4(c-3)+5=3+c-10 equation: 



4(c-3)+5=3+c-10

We move all terms to the left:

4(c-3)+5-(3+c-10)=0

We add all the numbers together, and all the variables

4(c-3)-(c-7)+5=0

We multiply parentheses

4c-(c-7)-12+5=0

We get rid of parentheses

4c-c+7-12+5=0

We add all the numbers together, and all the variables

3c=0

c=0/3

c=0

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