4(c-3)+7=4+c-9

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Solution for 4(c-3)+7=4+c-9 equation: 



4(c-3)+7=4+c-9

We move all terms to the left:

4(c-3)+7-(4+c-9)=0

We add all the numbers together, and all the variables

4(c-3)-(c-5)+7=0

We multiply parentheses

4c-(c-5)-12+7=0

We get rid of parentheses

4c-c+5-12+7=0

We add all the numbers together, and all the variables

3c=0

c=0/3

c=0

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