4(c-3)+8=6+c-10

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Solution for 4(c-3)+8=6+c-10 equation: 


Simplifying
4(c + -3) + 8 = 6 + c + -10

Reorder the terms:
4(-3 + c) + 8 = 6 + c + -10
(-3 * 4 + c * 4) + 8 = 6 + c + -10
(-12 + 4c) + 8 = 6 + c + -10

Reorder the terms:
-12 + 8 + 4c = 6 + c + -10

Combine like terms: -12 + 8 = -4
-4 + 4c = 6 + c + -10

Reorder the terms:
-4 + 4c = 6 + -10 + c

Combine like terms: 6 + -10 = -4
-4 + 4c = -4 + c

Add '4' to each side of the equation.
-4 + 4 + 4c = -4 + 4 + c

Combine like terms: -4 + 4 = 0
0 + 4c = -4 + 4 + c
4c = -4 + 4 + c

Combine like terms: -4 + 4 = 0
4c = 0 + c
4c = c

Solving
4c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
4c + -1c = c + -1c

Combine like terms: 4c + -1c = 3c
3c = c + -1c

Combine like terms: c + -1c = 0
3c = 0

Divide each side by '3'.
c = 0

Simplifying
c = 0

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