4(c-3)-3(2c+1)=

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Solution for 4(c-3)-3(2c+1)= equation:


Simplifying
4(c + -3) + -3(2c + 1) = 0

Reorder the terms:
4(-3 + c) + -3(2c + 1) = 0
(-3 * 4 + c * 4) + -3(2c + 1) = 0
(-12 + 4c) + -3(2c + 1) = 0

Reorder the terms:
-12 + 4c + -3(1 + 2c) = 0
-12 + 4c + (1 * -3 + 2c * -3) = 0
-12 + 4c + (-3 + -6c) = 0

Reorder the terms:
-12 + -3 + 4c + -6c = 0

Combine like terms: -12 + -3 = -15
-15 + 4c + -6c = 0

Combine like terms: 4c + -6c = -2c
-15 + -2c = 0

Solving
-15 + -2c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + -2c = 0 + 15

Combine like terms: -15 + 15 = 0
0 + -2c = 0 + 15
-2c = 0 + 15

Combine like terms: 0 + 15 = 15
-2c = 15

Divide each side by '-2'.
c = -7.5

Simplifying
c = -7.5

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