4(c-3)=3(3+c)

Solution for 4(c-3)=3(3+c) equation:

4(c-3)=3(3+c)

We move all terms to the left:

4(c-3)-(3(3+c))=0

We add all the numbers together, and all the variables

4(c-3)-(3(c+3))=0

We multiply parentheses

4c-(3(c+3))-12=0


We calculate terms in parentheses: -(3(c+3)), so:

3(c+3)

We multiply parentheses

3c+9

Back to the equation:

-(3c+9)


We get rid of parentheses

4c-3c-9-12=0

We add all the numbers together, and all the variables

c-21=0

We move all terms containing c to the left, all other terms to the right

c=21