4(c-3)=5(c-8)

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Solution for 4(c-3)=5(c-8) equation:


Simplifying
4(c + -3) = 5(c + -8)

Reorder the terms:
4(-3 + c) = 5(c + -8)
(-3 * 4 + c * 4) = 5(c + -8)
(-12 + 4c) = 5(c + -8)

Reorder the terms:
-12 + 4c = 5(-8 + c)
-12 + 4c = (-8 * 5 + c * 5)
-12 + 4c = (-40 + 5c)

Solving
-12 + 4c = -40 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
-12 + 4c + -5c = -40 + 5c + -5c

Combine like terms: 4c + -5c = -1c
-12 + -1c = -40 + 5c + -5c

Combine like terms: 5c + -5c = 0
-12 + -1c = -40 + 0
-12 + -1c = -40

Add '12' to each side of the equation.
-12 + 12 + -1c = -40 + 12

Combine like terms: -12 + 12 = 0
0 + -1c = -40 + 12
-1c = -40 + 12

Combine like terms: -40 + 12 = -28
-1c = -28

Divide each side by '-1'.
c = 28

Simplifying
c = 28

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