4(c-3)=6-2(1-c)

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Solution for 4(c-3)=6-2(1-c) equation: 



4(c-3)=6-2(1-c)

We move all terms to the left:

4(c-3)-(6-2(1-c))=0

We add all the numbers together, and all the variables

4(c-3)-(6-2(-1c+1))=0

We multiply parentheses

4c-(6-2(-1c+1))-12=0



We calculate terms in parentheses: -(6-2(-1c+1)), so:

6-2(-1c+1)

determiningTheFunctionDomain
-2(-1c+1)+6

We multiply parentheses

2c-2+6

We add all the numbers together, and all the variables

2c+4

Back to the equation:

-(2c+4)



We get rid of parentheses

4c-2c-4-12=0

We add all the numbers together, and all the variables

2c-16=0

We move all terms containing c to the left, all other terms to the right

2c=16

c=16/2

c=8

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