4(c-3)=6-2(1-c)

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Solution for 4(c-3)=6-2(1-c) equation:



4(c-3)=6-2(1-c)
We move all terms to the left:
4(c-3)-(6-2(1-c))=0
We add all the numbers together, and all the variables
4(c-3)-(6-2(-1c+1))=0
We multiply parentheses
4c-(6-2(-1c+1))-12=0
We calculate terms in parentheses: -(6-2(-1c+1)), so:
6-2(-1c+1)
determiningTheFunctionDomain -2(-1c+1)+6
We multiply parentheses
2c-2+6
We add all the numbers together, and all the variables
2c+4
Back to the equation:
-(2c+4)
We get rid of parentheses
4c-2c-4-12=0
We add all the numbers together, and all the variables
2c-16=0
We move all terms containing c to the left, all other terms to the right
2c=16
c=16/2
c=8

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