4(c-4)=-9c+12-5c

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Solution for 4(c-4)=-9c+12-5c equation:



4(c-4)=-9c+12-5c
We move all terms to the left:
4(c-4)-(-9c+12-5c)=0
We add all the numbers together, and all the variables
4(c-4)-(-14c+12)=0
We multiply parentheses
4c-(-14c+12)-16=0
We get rid of parentheses
4c+14c-12-16=0
We add all the numbers together, and all the variables
18c-28=0
We move all terms containing c to the left, all other terms to the right
18c=28
c=28/18
c=1+5/9

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