4(c-4)=3(c+5)

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Solution for 4(c-4)=3(c+5) equation:


Simplifying
4(c + -4) = 3(c + 5)

Reorder the terms:
4(-4 + c) = 3(c + 5)
(-4 * 4 + c * 4) = 3(c + 5)
(-16 + 4c) = 3(c + 5)

Reorder the terms:
-16 + 4c = 3(5 + c)
-16 + 4c = (5 * 3 + c * 3)
-16 + 4c = (15 + 3c)

Solving
-16 + 4c = 15 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-16 + 4c + -3c = 15 + 3c + -3c

Combine like terms: 4c + -3c = 1c
-16 + 1c = 15 + 3c + -3c

Combine like terms: 3c + -3c = 0
-16 + 1c = 15 + 0
-16 + 1c = 15

Add '16' to each side of the equation.
-16 + 16 + 1c = 15 + 16

Combine like terms: -16 + 16 = 0
0 + 1c = 15 + 16
1c = 15 + 16

Combine like terms: 15 + 16 = 31
1c = 31

Divide each side by '1'.
c = 31

Simplifying
c = 31

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