4(c-5)+12c=22-10c

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Solution for 4(c-5)+12c=22-10c equation: 



4(c-5)+12c=22-10c

We move all terms to the left:

4(c-5)+12c-(22-10c)=0

We add all the numbers together, and all the variables

4(c-5)+12c-(-10c+22)=0

We add all the numbers together, and all the variables

12c+4(c-5)-(-10c+22)=0

We multiply parentheses

12c+4c-(-10c+22)-20=0

We get rid of parentheses

12c+4c+10c-22-20=0

We add all the numbers together, and all the variables

26c-42=0

We move all terms containing c to the left, all other terms to the right

26c=42

c=42/26

c=1+8/13

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