4(c-5)+3=2+c-19

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Solution for 4(c-5)+3=2+c-19 equation: 


Simplifying
4(c + -5) + 3 = 2 + c + -19

Reorder the terms:
4(-5 + c) + 3 = 2 + c + -19
(-5 * 4 + c * 4) + 3 = 2 + c + -19
(-20 + 4c) + 3 = 2 + c + -19

Reorder the terms:
-20 + 3 + 4c = 2 + c + -19

Combine like terms: -20 + 3 = -17
-17 + 4c = 2 + c + -19

Reorder the terms:
-17 + 4c = 2 + -19 + c

Combine like terms: 2 + -19 = -17
-17 + 4c = -17 + c

Add '17' to each side of the equation.
-17 + 17 + 4c = -17 + 17 + c

Combine like terms: -17 + 17 = 0
0 + 4c = -17 + 17 + c
4c = -17 + 17 + c

Combine like terms: -17 + 17 = 0
4c = 0 + c
4c = c

Solving
4c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
4c + -1c = c + -1c

Combine like terms: 4c + -1c = 3c
3c = c + -1c

Combine like terms: c + -1c = 0
3c = 0

Divide each side by '3'.
c = 0

Simplifying
c = 0

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