4(c-5)+4=2+c-18

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Solution for 4(c-5)+4=2+c-18 equation:


4(c-5)+4=2+c-18

We simplify the equation to the form, which is simple to understand 
4(c-5)+4=2+c-18

Reorder the terms in parentheses
+(+4c-20)+4=2+c-18

Remove unnecessary parentheses
+4c-20+4=+2+c-18

We move all terms containing c to the left and all other terms to the right. 
+4c-1c=+2-18+20-4

We simplify left and right side of the equation. 
+3c=0

We divide both sides of the equation by 3 to get c. 
c=0

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