4(c-5)+6=3+c-17

Solution for 4(c-5)+6=3+c-17 equation:

Simplifying
4(c + -5) + 6 = 3 + c + -17

Reorder the terms:
4(-5 + c) + 6 = 3 + c + -17
(-5 * 4 + c * 4) + 6 = 3 + c + -17
(-20 + 4c) + 6 = 3 + c + -17

Reorder the terms:
-20 + 6 + 4c = 3 + c + -17

Combine like terms: -20 + 6 = -14
-14 + 4c = 3 + c + -17

Reorder the terms:
-14 + 4c = 3 + -17 + c

Combine like terms: 3 + -17 = -14
-14 + 4c = -14 + c

Add '14' to each side of the equation.
-14 + 14 + 4c = -14 + 14 + c

Combine like terms: -14 + 14 = 0
0 + 4c = -14 + 14 + c
4c = -14 + 14 + c

Combine like terms: -14 + 14 = 0
4c = 0 + c
4c = c

Solving
4c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
4c + -1c = c + -1c

Combine like terms: 4c + -1c = 3c
3c = c + -1c

Combine like terms: c + -1c = 0
3c = 0

Divide each side by '3'.
c = 0

Simplifying
c = 0