4(c-5)-2(3c+5)=6

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Solution for 4(c-5)-2(3c+5)=6 equation:


Simplifying
4(c + -5) + -2(3c + 5) = 6

Reorder the terms:
4(-5 + c) + -2(3c + 5) = 6
(-5 * 4 + c * 4) + -2(3c + 5) = 6
(-20 + 4c) + -2(3c + 5) = 6

Reorder the terms:
-20 + 4c + -2(5 + 3c) = 6
-20 + 4c + (5 * -2 + 3c * -2) = 6
-20 + 4c + (-10 + -6c) = 6

Reorder the terms:
-20 + -10 + 4c + -6c = 6

Combine like terms: -20 + -10 = -30
-30 + 4c + -6c = 6

Combine like terms: 4c + -6c = -2c
-30 + -2c = 6

Solving
-30 + -2c = 6

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '30' to each side of the equation.
-30 + 30 + -2c = 6 + 30

Combine like terms: -30 + 30 = 0
0 + -2c = 6 + 30
-2c = 6 + 30

Combine like terms: 6 + 30 = 36
-2c = 36

Divide each side by '-2'.
c = -18

Simplifying
c = -18

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