4(c-5)-3(c-1)=2(c+1)

Solution for 4(c-5)-3(c-1)=2(c+1) equation:

4(c-5)-3(c-1)=2(c+1)

We move all terms to the left:

4(c-5)-3(c-1)-(2(c+1))=0

We multiply parentheses

4c-3c-(2(c+1))-20+3=0


We calculate terms in parentheses: -(2(c+1)), so:

2(c+1)

We multiply parentheses

2c+2

Back to the equation:

-(2c+2)


We add all the numbers together, and all the variables

c-(2c+2)-17=0

We get rid of parentheses

c-2c-2-17=0

We add all the numbers together, and all the variables

-1c-19=0

We move all terms containing c to the left, all other terms to the right

-c=19

c=19/-1

c=-19