4(c-5)-6(c+1)=7-2c

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Solution for 4(c-5)-6(c+1)=7-2c equation: 


Simplifying
4(c + -5) + -6(c + 1) = 7 + -2c

Reorder the terms:
4(-5 + c) + -6(c + 1) = 7 + -2c
(-5 * 4 + c * 4) + -6(c + 1) = 7 + -2c
(-20 + 4c) + -6(c + 1) = 7 + -2c

Reorder the terms:
-20 + 4c + -6(1 + c) = 7 + -2c
-20 + 4c + (1 * -6 + c * -6) = 7 + -2c
-20 + 4c + (-6 + -6c) = 7 + -2c

Reorder the terms:
-20 + -6 + 4c + -6c = 7 + -2c

Combine like terms: -20 + -6 = -26
-26 + 4c + -6c = 7 + -2c

Combine like terms: 4c + -6c = -2c
-26 + -2c = 7 + -2c

Add '2c' to each side of the equation.
-26 + -2c + 2c = 7 + -2c + 2c

Combine like terms: -2c + 2c = 0
-26 + 0 = 7 + -2c + 2c
-26 = 7 + -2c + 2c

Combine like terms: -2c + 2c = 0
-26 = 7 + 0
-26 = 7

Solving
-26 = 7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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