4(c-5)=3(c-4)

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Solution for 4(c-5)=3(c-4) equation:


Simplifying
4(c + -5) = 3(c + -4)

Reorder the terms:
4(-5 + c) = 3(c + -4)
(-5 * 4 + c * 4) = 3(c + -4)
(-20 + 4c) = 3(c + -4)

Reorder the terms:
-20 + 4c = 3(-4 + c)
-20 + 4c = (-4 * 3 + c * 3)
-20 + 4c = (-12 + 3c)

Solving
-20 + 4c = -12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-20 + 4c + -3c = -12 + 3c + -3c

Combine like terms: 4c + -3c = 1c
-20 + 1c = -12 + 3c + -3c

Combine like terms: 3c + -3c = 0
-20 + 1c = -12 + 0
-20 + 1c = -12

Add '20' to each side of the equation.
-20 + 20 + 1c = -12 + 20

Combine like terms: -20 + 20 = 0
0 + 1c = -12 + 20
1c = -12 + 20

Combine like terms: -12 + 20 = 8
1c = 8

Divide each side by '1'.
c = 8

Simplifying
c = 8

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