4(c=1)+2c=7+3(c-1)

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Solution for 4(c=1)+2c=7+3(c-1) equation: 



4(c=1)+2c=7+3(c-1)

We move all terms to the left:

4(c-(1)+2c)=0

We add all the numbers together, and all the variables

4(3c-1)=0

We multiply parentheses

12c-4=0

We move all terms containing c to the left, all other terms to the right

12c=4

c=4/12

c=1/3

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