4(d+1)=32

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Solution for 4(d+1)=32 equation: 



4(d+1)=32

We move all terms to the left:

4(d+1)-(32)=0

We multiply parentheses

4d+4-32=0

We add all the numbers together, and all the variables

4d-28=0

We move all terms containing d to the left, all other terms to the right

4d=28

d=28/4

d=7

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