4(d+2)-2d=3(2+d

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Solution for 4(d+2)-2d=3(2+d equation: 



4(d+2)-2d=3(2+d

We move all terms to the left:

4(d+2)-2d-(3(2+d)=0

We add all the numbers together, and all the variables

4(d+2)-2d-(3(d+2)=0

We add all the numbers together, and all the variables

-2d+4(d+2)-(3(d+2)=0

We multiply parentheses

-2d+4d-(3(d+2)+8=0

We add all the numbers together, and all the variables

2d-(3(d+2)+8=0

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