4(d+2)=2(d-3)

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Solution for 4(d+2)=2(d-3) equation: 



4(d+2)=2(d-3)

We move all terms to the left:

4(d+2)-(2(d-3))=0

We multiply parentheses

4d-(2(d-3))+8=0



We calculate terms in parentheses: -(2(d-3)), so:

2(d-3)

We multiply parentheses

2d-6

Back to the equation:

-(2d-6)



We get rid of parentheses

4d-2d+6+8=0

We add all the numbers together, and all the variables

2d+14=0

We move all terms containing d to the left, all other terms to the right

2d=-14

d=-14/2

d=-7

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