4(d+3)+5(d-7)=67

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Solution for 4(d+3)+5(d-7)=67 equation: 



4(d+3)+5(d-7)=67

We move all terms to the left:

4(d+3)+5(d-7)-(67)=0

We multiply parentheses

4d+5d+12-35-67=0

We add all the numbers together, and all the variables

9d-90=0

We move all terms containing d to the left, all other terms to the right

9d=90

d=90/9

d=10

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