4(d+4)+2=3(d+1)

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Solution for 4(d+4)+2=3(d+1) equation:


Simplifying
4(d + 4) + 2 = 3(d + 1)

Reorder the terms:
4(4 + d) + 2 = 3(d + 1)
(4 * 4 + d * 4) + 2 = 3(d + 1)
(16 + 4d) + 2 = 3(d + 1)

Reorder the terms:
16 + 2 + 4d = 3(d + 1)

Combine like terms: 16 + 2 = 18
18 + 4d = 3(d + 1)

Reorder the terms:
18 + 4d = 3(1 + d)
18 + 4d = (1 * 3 + d * 3)
18 + 4d = (3 + 3d)

Solving
18 + 4d = 3 + 3d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-3d' to each side of the equation.
18 + 4d + -3d = 3 + 3d + -3d

Combine like terms: 4d + -3d = 1d
18 + 1d = 3 + 3d + -3d

Combine like terms: 3d + -3d = 0
18 + 1d = 3 + 0
18 + 1d = 3

Add '-18' to each side of the equation.
18 + -18 + 1d = 3 + -18

Combine like terms: 18 + -18 = 0
0 + 1d = 3 + -18
1d = 3 + -18

Combine like terms: 3 + -18 = -15
1d = -15

Divide each side by '1'.
d = -15

Simplifying
d = -15

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