4(d+5)=2(2d+3)

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Solution for 4(d+5)=2(2d+3) equation: 



4(d+5)=2(2d+3)

We move all terms to the left:

4(d+5)-(2(2d+3))=0

We multiply parentheses

4d-(2(2d+3))+20=0



We calculate terms in parentheses: -(2(2d+3)), so:

2(2d+3)

We multiply parentheses

4d+6

Back to the equation:

-(4d+6)



We get rid of parentheses

4d-4d-6+20=0

We add all the numbers together, and all the variables

14!=0

There is no solution for this equation

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