4(d+5)=29

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Solution for 4(d+5)=29 equation: 



4(d+5)=29

We move all terms to the left:

4(d+5)-(29)=0

We multiply parentheses

4d+20-29=0

We add all the numbers together, and all the variables

4d-9=0

We move all terms containing d to the left, all other terms to the right

4d=9

d=9/4

d=2+1/4

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