4(d-12)+-8=8

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Solution for 4(d-12)+-8=8 equation:



4(d-12)+-8=8
We move all terms to the left:
4(d-12)+-8-(8)=0
determiningTheFunctionDomain 4(d-12)-8-8+=0
We add all the numbers together, and all the variables
4(d-12)=0
We multiply parentheses
4d-48=0
We move all terms containing d to the left, all other terms to the right
4d=48
d=48/4
d=12

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