4(d-12)+-8=8

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Solution for 4(d-12)+-8=8 equation: 



4(d-12)+-8=8

We move all terms to the left:

4(d-12)+-8-(8)=0

determiningTheFunctionDomain
4(d-12)-8-8+=0

We add all the numbers together, and all the variables

4(d-12)=0

We multiply parentheses

4d-48=0

We move all terms containing d to the left, all other terms to the right

4d=48

d=48/4

d=12

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