4(d-4)+2=3(d+1)

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Solution for 4(d-4)+2=3(d+1) equation:


Simplifying
4(d + -4) + 2 = 3(d + 1)

Reorder the terms:
4(-4 + d) + 2 = 3(d + 1)
(-4 * 4 + d * 4) + 2 = 3(d + 1)
(-16 + 4d) + 2 = 3(d + 1)

Reorder the terms:
-16 + 2 + 4d = 3(d + 1)

Combine like terms: -16 + 2 = -14
-14 + 4d = 3(d + 1)

Reorder the terms:
-14 + 4d = 3(1 + d)
-14 + 4d = (1 * 3 + d * 3)
-14 + 4d = (3 + 3d)

Solving
-14 + 4d = 3 + 3d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-3d' to each side of the equation.
-14 + 4d + -3d = 3 + 3d + -3d

Combine like terms: 4d + -3d = 1d
-14 + 1d = 3 + 3d + -3d

Combine like terms: 3d + -3d = 0
-14 + 1d = 3 + 0
-14 + 1d = 3

Add '14' to each side of the equation.
-14 + 14 + 1d = 3 + 14

Combine like terms: -14 + 14 = 0
0 + 1d = 3 + 14
1d = 3 + 14

Combine like terms: 3 + 14 = 17
1d = 17

Divide each side by '1'.
d = 17

Simplifying
d = 17

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