4(d-4)+2=3(d+11)

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Solution for 4(d-4)+2=3(d+11) equation: 



4(d-4)+2=3(d+11)

We move all terms to the left:

4(d-4)+2-(3(d+11))=0

We multiply parentheses

4d-(3(d+11))-16+2=0



We calculate terms in parentheses: -(3(d+11)), so:

3(d+11)

We multiply parentheses

3d+33

Back to the equation:

-(3d+33)



We add all the numbers together, and all the variables

4d-(3d+33)-14=0

We get rid of parentheses

4d-3d-33-14=0

We add all the numbers together, and all the variables

d-47=0

We move all terms containing d to the left, all other terms to the right

d=47

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