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4(d-4)+2=3(d-1)
We move all terms to the left:
4(d-4)+2-(3(d-1))=0
We multiply parentheses
4d-(3(d-1))-16+2=0
We calculate terms in parentheses: -(3(d-1)), so:We add all the numbers together, and all the variables
3(d-1)
We multiply parentheses
3d-3
Back to the equation:
-(3d-3)
4d-(3d-3)-14=0
We get rid of parentheses
4d-3d+3-14=0
We add all the numbers together, and all the variables
d-11=0
We move all terms containing d to the left, all other terms to the right
d=11
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