4(d-4)+2=3d+3

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Solution for 4(d-4)+2=3d+3 equation: 



4(d-4)+2=3d+3

We move all terms to the left:

4(d-4)+2-(3d+3)=0

We multiply parentheses

4d-(3d+3)-16+2=0

We get rid of parentheses

4d-3d-3-16+2=0

We add all the numbers together, and all the variables

d-17=0

We move all terms containing d to the left, all other terms to the right

d=17

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