4(d=2)-2d=3(2+d)

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Solution for 4(d=2)-2d=3(2+d) equation: 



4(d=2)-2d=3(2+d)

We move all terms to the left:

4(d-(2)-2d)=0

We add all the numbers together, and all the variables

4(-1d-2)=0

We multiply parentheses

-4d-8=0

We move all terms containing d to the left, all other terms to the right

-4d=8

d=8/-4

d=-2

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