4(e-5)+2e+15-3(6+e)=-5(e+4)+11e

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Solution for 4(e-5)+2e+15-3(6+e)=-5(e+4)+11e equation: 



4(e-5)+2e+15-3(6+e)=-5(e+4)+11e

We move all terms to the left:

4(e-5)+2e+15-3(6+e)-(-5(e+4)+11e)=0

We add all the numbers together, and all the variables

4(e-5)+2e-3(e+6)-(-5(e+4)+11e)+15=0

We add all the numbers together, and all the variables

2e+4(e-5)-3(e+6)-(-5(e+4)+11e)+15=0

We multiply parentheses

2e+4e-3e-(-5(e+4)+11e)-20-18+15=0



We calculate terms in parentheses: -(-5(e+4)+11e), so:

-5(e+4)+11e

We add all the numbers together, and all the variables

11e-5(e+4)

We multiply parentheses

11e-5e-20

We add all the numbers together, and all the variables

6e-20

Back to the equation:

-(6e-20)



We add all the numbers together, and all the variables

3e-(6e-20)-23=0

We get rid of parentheses

3e-6e+20-23=0

We add all the numbers together, and all the variables

-3e-3=0

We move all terms containing e to the left, all other terms to the right

-3e=3

e=3/-3

e=-1

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