4(f+1)+3f=12

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Solution for 4(f+1)+3f=12 equation: 



4(f+1)+3f=12

We move all terms to the left:

4(f+1)+3f-(12)=0

We add all the numbers together, and all the variables

3f+4(f+1)-12=0

We multiply parentheses

3f+4f+4-12=0

We add all the numbers together, and all the variables

7f-8=0

We move all terms containing f to the left, all other terms to the right

7f=8

f=8/7

f=1+1/7

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