4(f+1)-7=3(f-1)+f

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Solution for 4(f+1)-7=3(f-1)+f equation:



4(f+1)-7=3(f-1)+f
We move all terms to the left:
4(f+1)-7-(3(f-1)+f)=0
We multiply parentheses
4f-(3(f-1)+f)+4-7=0
We calculate terms in parentheses: -(3(f-1)+f), so:
3(f-1)+f
We add all the numbers together, and all the variables
f+3(f-1)
We multiply parentheses
f+3f-3
We add all the numbers together, and all the variables
4f-3
Back to the equation:
-(4f-3)
We add all the numbers together, and all the variables
4f-(4f-3)-3=0
We get rid of parentheses
4f-4f+3-3=0
We add all the numbers together, and all the variables
=0
f=0/1
f=0

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