4(f+3)+5=17++4f

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Solution for 4(f+3)+5=17++4f equation:


4(f+3)+5=17++4f

We simplify the equation to the form, which is simple to understand 
4(f+3)+5=17+4f

Reorder the terms in parentheses
+(+4f+12)+5=17+4f

Remove unnecessary parentheses
+4f+12+5=+17+4f

We move all terms containing f to the left and all other terms to the right. 
+4f-4f=+17-12-5

We simplify left and right side of the equation. 
f=0

0=0

This equation is an identity, so all real numbers are solutions.

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