4(f+3)=20

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Solution for 4(f+3)=20 equation: 



4(f+3)=20

We move all terms to the left:

4(f+3)-(20)=0

We multiply parentheses

4f+12-20=0

We add all the numbers together, and all the variables

4f-8=0

We move all terms containing f to the left, all other terms to the right

4f=8

f=8/4

f=2

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