4(f+5)=32

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Solution for 4(f+5)=32 equation: 



4(f+5)=32

We move all terms to the left:

4(f+5)-(32)=0

We multiply parentheses

4f+20-32=0

We add all the numbers together, and all the variables

4f-12=0

We move all terms containing f to the left, all other terms to the right

4f=12

f=12/4

f=3

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