4(f-3)-1=2(f+5)-1

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Solution for 4(f-3)-1=2(f+5)-1 equation: 



4(f-3)-1=2(f+5)-1

We move all terms to the left:

4(f-3)-1-(2(f+5)-1)=0

We multiply parentheses

4f-(2(f+5)-1)-12-1=0



We calculate terms in parentheses: -(2(f+5)-1), so:

2(f+5)-1

We multiply parentheses

2f+10-1

We add all the numbers together, and all the variables

2f+9

Back to the equation:

-(2f+9)



We add all the numbers together, and all the variables

4f-(2f+9)-13=0

We get rid of parentheses

4f-2f-9-13=0

We add all the numbers together, and all the variables

2f-22=0

We move all terms containing f to the left, all other terms to the right

2f=22

f=22/2

f=11

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