4(g+1)=2(g-1)-3

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Solution for 4(g+1)=2(g-1)-3 equation: 



4(g+1)=2(g-1)-3

We move all terms to the left:

4(g+1)-(2(g-1)-3)=0

We multiply parentheses

4g-(2(g-1)-3)+4=0



We calculate terms in parentheses: -(2(g-1)-3), so:

2(g-1)-3

We multiply parentheses

2g-2-3

We add all the numbers together, and all the variables

2g-5

Back to the equation:

-(2g-5)



We get rid of parentheses

4g-2g+5+4=0

We add all the numbers together, and all the variables

2g+9=0

We move all terms containing g to the left, all other terms to the right

2g=-9

g=-9/2

g=-4+1/2

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