4(g+1)=8(g-3)

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Solution for 4(g+1)=8(g-3) equation: 



4(g+1)=8(g-3)

We move all terms to the left:

4(g+1)-(8(g-3))=0

We multiply parentheses

4g-(8(g-3))+4=0



We calculate terms in parentheses: -(8(g-3)), so:

8(g-3)

We multiply parentheses

8g-24

Back to the equation:

-(8g-24)



We get rid of parentheses

4g-8g+24+4=0

We add all the numbers together, and all the variables

-4g+28=0

We move all terms containing g to the left, all other terms to the right

-4g=-28

g=-28/-4

g=+7

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