4(g-2)+1=g-6=3g

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Solution for 4(g-2)+1=g-6=3g equation: 



4(g-2)+1=g-6=3g

We move all terms to the left:

4(g-2)+1-(g-6)=0

We multiply parentheses

4g-(g-6)-8+1=0

We get rid of parentheses

4g-g+6-8+1=0

We add all the numbers together, and all the variables

3g-1=0

We move all terms containing g to the left, all other terms to the right

3g=1

g=1/3

g=1/3

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