4(h+1)-(2h+3i)=

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Solution for 4(h+1)-(2h+3i)= equation:


Simplifying
4(h + 1) + -1(2h + 3i) = 0

Reorder the terms:
4(1 + h) + -1(2h + 3i) = 0
(1 * 4 + h * 4) + -1(2h + 3i) = 0
(4 + 4h) + -1(2h + 3i) = 0
4 + 4h + (2h * -1 + 3i * -1) = 0
4 + 4h + (-2h + -3i) = 0

Combine like terms: 4h + -2h = 2h
4 + 2h + -3i = 0

Solving
4 + 2h + -3i = 0

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 2h + -4 + -3i = 0 + -4

Reorder the terms:
4 + -4 + 2h + -3i = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 2h + -3i = 0 + -4
2h + -3i = 0 + -4

Combine like terms: 0 + -4 = -4
2h + -3i = -4

Add '3i' to each side of the equation.
2h + -3i + 3i = -4 + 3i

Combine like terms: -3i + 3i = 0
2h + 0 = -4 + 3i
2h = -4 + 3i

Divide each side by '2'.
h = -2 + 1.5i

Simplifying
h = -2 + 1.5i

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