4(h+1)=32

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Solution for 4(h+1)=32 equation: 



4(h+1)=32

We move all terms to the left:

4(h+1)-(32)=0

We multiply parentheses

4h+4-32=0

We add all the numbers together, and all the variables

4h-28=0

We move all terms containing h to the left, all other terms to the right

4h=28

h=28/4

h=7

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