4(h+1,5)=3(h+11/3)

Solution for 4(h+1,5)=3(h+11/3) equation:

4(h+1.5)=3(h+11/3)

We move all terms to the left:

4(h+1.5)-(3(h+11/3))=0

We add all the numbers together, and all the variables

4(h+1.5)-(3(+h+11/3))=0

We multiply parentheses

4h-(3(+h+11/3))+6=0

We multiply all the terms by the denominator


4h*3))-(3(+h+11+6*3))=0

We add all the numbers together, and all the variables

4h*3))-(3(h+29))=0

We add all the numbers together, and all the variables

4h*3))-(3(h=0

Wy multiply elements

12h^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{0}{24}=0$