4(h+2)+9(3h+4)=-18

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Solution for 4(h+2)+9(3h+4)=-18 equation: 



4(h+2)+9(3h+4)=-18

We move all terms to the left:

4(h+2)+9(3h+4)-(-18)=0

We add all the numbers together, and all the variables

4(h+2)+9(3h+4)+18=0

We multiply parentheses

4h+27h+8+36+18=0

We add all the numbers together, and all the variables

31h+62=0

We move all terms containing h to the left, all other terms to the right

31h=-62

h=-62/31

h=-2

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