4(h+2)+h+1=-2(4-2h)

Solution for 4(h+2)+h+1=-2(4-2h) equation:

4(h+2)+h+1=-2(4-2h)

We move all terms to the left:

4(h+2)+h+1-(-2(4-2h))=0

We add all the numbers together, and all the variables

4(h+2)+h-(-2(-2h+4))+1=0

We add all the numbers together, and all the variables

h+4(h+2)-(-2(-2h+4))+1=0

We multiply parentheses

h+4h-(-2(-2h+4))+8+1=0


We calculate terms in parentheses: -(-2(-2h+4)), so:

-2(-2h+4)

We multiply parentheses

4h-8

Back to the equation:

-(4h-8)


We add all the numbers together, and all the variables

5h-(4h-8)+9=0

We get rid of parentheses

5h-4h+8+9=0

We add all the numbers together, and all the variables

h+17=0

We move all terms containing h to the left, all other terms to the right

h=-17