4(h+3)+1=2(3+2h)

Solution for 4(h+3)+1=2(3+2h) equation:

4(h+3)+1=2(3+2h)

We move all terms to the left:

4(h+3)+1-(2(3+2h))=0

We add all the numbers together, and all the variables

4(h+3)-(2(2h+3))+1=0

We multiply parentheses

4h-(2(2h+3))+12+1=0


We calculate terms in parentheses: -(2(2h+3)), so:

2(2h+3)

We multiply parentheses

4h+6

Back to the equation:

-(4h+6)


We add all the numbers together, and all the variables

4h-(4h+6)+13=0

We get rid of parentheses

4h-4h-6+13=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation